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1int: n; 2array [1..n] of var 1..n: q; % 在第i列的皇后在q[i]上 3 4include "alldifferent.mzn"; 5 6constraint alldifferent(q); % distinct rows 7constraint alldifferent([ q[i] + i | i in 1..n]); % distinct diagonals 8constraint alldifferent([ q[i] - i | i in 1..n]); % upwards+downwards 9 10include "lex_lesseq.mzn"; 11 12% 可选的布尔模型: 13% 映射每一个位置 i,j到一个布尔变量上来表示在i,j上是否有一个皇后 14array[1..n,1..n] of var bool: qb; 15 16% 连通约束 17constraint forall (i,j in 1..n) ( qb[i,j] <-> (q[i]=j) ); 18 19% 字典排序对称性破缺 20constraint 21 lex_lesseq(array1d(qb), [ qb[j,i] | i,j in 1..n ]) 22/\ lex_lesseq(array1d(qb), [ qb[i,j] | i in reverse(1..n), j in 1..n ]) 23/\ lex_lesseq(array1d(qb), [ qb[j,i] | i in 1..n, j in reverse(1..n) ]) 24/\ lex_lesseq(array1d(qb), [ qb[i,j] | i in 1..n, j in reverse(1..n) ]) 25/\ lex_lesseq(array1d(qb), [ qb[j,i] | i in reverse(1..n), j in 1..n ]) 26/\ lex_lesseq(array1d(qb), [ qb[i,j] | i,j in reverse(1..n) ]) 27/\ lex_lesseq(array1d(qb), [ qb[j,i] | i,j in reverse(1..n) ]) 28; 29 30% 搜索 31solve :: int_search(q, first_fail, indomain_min, complete) 32 satisfy; 33output [ if fix(q[j]) == i then "Q" else "." endif ++ 34 if j == n then "\n" else "" endif | i,j in 1..n]