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1predicate fzn_cost_regular(array[int] of var int: x, int: Q, int: S,
2 array[int,int] of int: d, int: q0, set of int: F,
3 array[int,int] of int: c, var int: C) =
4 let {
5 % If x has index set m..n-1, then a[m] holds the initial state
6 % (q0), and a[i+1] holds the state we're in after processing
7 % x[i]. If a[n] is in F, then we succeed (ie. accept the string).
8 int: m = min(index_set(x));
9 int: n = max(index_set(x)) + 1;
10 array[m..n] of var 1..Q: a;
11 % cc[i+1] holds the accumulated cost of edges taken process up to x[i]
12 array[m..n] of var int: cc;
13 } in
14 a[m] = q0 /\ % Set a[0].
15 cc[m] = 0 /\ % initially zero cost
16 forall(i in index_set(x)) (
17 x[i] in 1..S /\ % Do this in case it's a var.
18 a[i+1] = d[a[i], x[i]] /\ % Determine a[i+1].
19 cc[i+1] = c[a[i],x[i]] + cc[i] % Calculate new cost sum
20 ) /\
21 a[n] in F /\ % Check the final state is in F.
22 C = cc[n] % return final cost
23 ;