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1predicate fzn_subgraph_reif(array[int] of $$N: from, array[int] of $$N: to,
2 array[$$N] of var bool: ns, array[int] of var bool: es,
3 var bool: b) =
4 b <-> forall(e in index_set(from)) (
5 (es[e] -> ns[from[e]]) /\ (es[e] -> ns[to[e]])
6 );
7
8%-----------------------------------------------------------------------------%